Need help- Force of friction in a circle.

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SUMMARY

The discussion focuses on calculating the force of friction required to keep a 45-kg worker on a merry-go-round moving at a speed of 4.1 m/s while standing 6.3 meters from the center. The relevant equations include the centripetal acceleration formula, A_c = v^2/r, and the friction coefficient formula, μ = v^2/(rg). The participant correctly identifies the need to use these equations to solve for the force of friction but expresses uncertainty about the relevance of the radius in the problem.

PREREQUISITES
  • Understanding of Newton's second law (f=ma)
  • Knowledge of centripetal acceleration (A_c = v^2/r)
  • Familiarity with the concept of friction coefficient (μ)
  • Basic algebra for manipulating equations
NEXT STEPS
  • Calculate the centripetal force using F_c = m * A_c
  • Explore the relationship between friction and centripetal force in circular motion
  • Investigate real-world applications of friction in circular motion scenarios
  • Review examples of similar physics problems involving circular motion and friction
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for examples of friction in practical applications.

Socom
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Homework Statement


A 45-kg merry-go-round worker stands on the ride's platform 6.3m from the center. If her speed as she goes around the circle is 4.1 m/s, what is the force of friction necessary to keep her from falling off the platform?


Homework Equations


f=ma
Ac=v^2/r
mu=v^2/rg (derived from [mu]g=v^2/r


The Attempt at a Solution


I don't believe the 6.3m is relevant to the problem.

I believe Fnet=sigmaFx=theta=m*a

I am not really sure how to attack this problem and some help would be very nice.
 
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Socom said:

Homework Statement


A 45-kg merry-go-round worker stands on the ride's platform 6.3m from the center. If her speed as she goes around the circle is 4.1 m/s, what is the force of friction necessary to keep her from falling off the platform?

Homework Equations


f=ma
Ac=v^2/r
mu=v^2/rg (derived from [mu]g=v^2/r

The Attempt at a Solution


I don't believe the 6.3m is relevant to the problem.

I believe Fnet=sigmaFx=theta=m*a

I am not really sure how to attack this problem and some help would be very nice.

You got the right equation:

[tex]\mu = \frac{v^2}{rg}[/tex]

now tell me... what does the r mean in:

[tex]A_c = \frac{v^2}{r}[/tex]
 

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