Need help in deriving this reduction formula

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SUMMARY

The discussion focuses on deriving the reduction formula for the integral of sine raised to the power of n, specifically I(n) = ∫ (sinx)^n dx from 0 to π/2. The goal is to prove that I(n+2) = I(n) * (n+1)/(n+2). Various attempts using integration by parts were made, including substituting sin^2(x) with 1 - cos^2(x), but these did not yield the desired result. The final suggestion involves starting with I(n+2) and applying integration by parts to evaluate the integral.

PREREQUISITES
  • Understanding of definite integrals, specifically from 0 to π/2.
  • Familiarity with the concept of integration by parts.
  • Knowledge of trigonometric identities, particularly sin^2(x) and cos^2(x).
  • Ability to manipulate expressions involving subscripts and superscripts in mathematical notation.
NEXT STEPS
  • Learn the application of integration by parts in trigonometric integrals.
  • Study the derivation of reduction formulas for integrals involving powers of sine and cosine.
  • Explore the use of trigonometric identities in simplifying integrals.
  • Practice solving integrals of the form I(n) = ∫ (sinx)^n dx to reinforce understanding.
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Students studying calculus, particularly those focusing on integral calculus and reduction formulas, as well as educators looking for examples of integration techniques involving trigonometric functions.

hms.tech
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It might be difficult for you to read this integral in non latex form, but i'll try my best.
As i don't know how to write this in latex form, assume "for this problem" that I(n) is pronounced as "I subscript n" or nth term of I.


Homework Statement



I(n)=∫ (sinx)^n dx [with limits of the integral as : from zero (0) to ∏/2 (pi/2)

Using the above equation, it is required to prove that :

I(n+2)= I(n) * (n+1)/(n+2) [again , I(n) means I subscript n ie nth term of a sequence]

Homework Equations


the formula for integration by parts


The Attempt at a Solution



I have tried to integrate it by parts using various ways but all of them failed to prove the required result.
One of them was :
∫ [sin^-2(x)*(sin(x))^(n+2)] dx [with the same limits ofcourse]

even after subsituting 1-cos^2(x) for sin^2(x) the problem could not be solved,
please help me solve it.
 
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hms.tech said:
It might be difficult for you to read this integral in non latex form, but I'll try my best.
As i don't know how to write this in latex form, assume "for this problem" that I(n) is pronounced as "I subscript n" or nth term of I.


Homework Statement



I(n)=∫ (sinx)^n dx [with limits of the integral as : from zero (0) to ∏/2 (pi/2)

Using the above equation, it is required to prove that :

I(n+2)= I(n) * (n+1)/(n+2) [again , I(n) means I subscript n ie nth term of a sequence]

Homework Equations


the formula for integration by parts


The Attempt at a Solution



I have tried to integrate it by parts using various ways but all of them failed to prove the required result.
One of them was :
∫ [sin^-2(x)*(sin(x))^(n+2)] dx [with the same limits of course]

even after substituting 1-cos^2(x) for sin^2(x) the problem could not be solved,
please help me solve it.
Start with In+2.
Even without LaTeX, you can do SUBSCRIPTS and SUPERSCRIPTS by using the X2 and X2 buttons in the 'Go Advanced' message window.

[itex]\displaystyle I_{n+2}=\int\sin^{n+2}(x)\,dx=\int(1-\cos^2(x))\sin^{n}(x)\,dx=I_n-\int\cos^2(x)\sin^{n}(x)\,dx[/itex]

Evaluate that last integral using integration by parts.
u=cos(x), dv=cos(x)sinn(x) dx​
 

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