Need help in the physic HW question

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SUMMARY

The discussion centers on calculating the impulse exerted by a bullet on a block during a collision. The bullet has a mass of 17.6 g and an initial speed of 565 m/s, exiting the block at 524 m/s. The impulse is defined as the change in momentum, calculated using the formula Impulse = mv_f - mv_i. The correct approach involves determining the change in momentum of the block, not the bullet, to find the impulse exerted by the bullet on the block.

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  • Understanding of impulse and momentum concepts
  • Familiarity with the formula Impulse = Δ Momentum
  • Knowledge of mass and velocity units (grams and meters per second)
  • Basic principles of collisions in physics
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  • Explore the relationship between force, time, and impulse
  • Review examples of momentum changes in various collision types
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Homework Statement



A bullet of mass m = 17.6 g traveling horizontally at speed vo = 565 m/s strikes a block of mass M = 678 g sitting on a frictionless, horizontal table. This time, however, it comes out the other side of the block at speed v = 524 m/s.

Calculate J, the magnitude of the impulse exerted by the bullet on the block.

2. Homework Equations

Hm...

Impulse = Momentum = Ft = mv_f - mv_i

3. The Attempt at a Solution

I think that the impulse is same as the momentum. I think that is...

Impulse = mv_f - mv_i

I got -0.722 but it's incorrect. My professor said that impulse can't be negative because time is positive and force is positive.

But it seems like I'm on the wrong path. (This is from the previous question. Seems like nobody wants to pay attention, so I ask again.)
 
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Impulse is the change in momentum during a collision. But the question's asking for the impulse on the bullet by the block, not the other way around. So you'll have to find the change in momentum of the block first.
 
NasuSama said:

Homework Statement



A bullet of mass m = 17.6 g traveling horizontally at speed vo = 565 m/s strikes a block of mass M = 678 g sitting on a frictionless, horizontal table. This time, however, it comes out the other side of the block at speed v = 524 m/s.

Calculate J, the magnitude of the impulse exerted by the bullet on the block.

2. Homework Equations

Hm...

Impulse = Δ Momentum → Ft = mv_f - mv_i

3. The Attempt at a Solution

I think that the impulse is same as the momentum. I think that is...

Impulse = mv_f - mv_i

I got -0.722 but it's incorrect.
This is the impulse exerted on the bullet by the block.
My professor said that impulse can't be negative because time is positive and force is positive.

But it seems like I'm on the wrong path. (This is from the previous question. Seems like nobody wants to pay attention, so I ask again.)
 

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