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Need help on Motion in a Resistive Medium

  1. Sep 22, 2008 #1
    1. The motion of a body falling from rest in a resistive medium is dv/dt = Bv - Av^2.

    2. Find it's initial acceleration.
    Find the velocity at which the acceleration becomes zero.

    3. B and A are constants.

    dv/dt = acceleration = Bv - Av^2.

    vf = vi + at
    vf = 0 + Bv - Av^2(t)
    vf = Bv - Av^2(t)

    Where am I going with this?
  2. jcsd
  3. Sep 22, 2008 #2


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    Hi eyvhgi557r! :smile:
    hmm … nowhere! :rolleyes:

    those equations only apply to uniform acceleration …

    you need to solve dv/dt = Bv - Av^2 in the usual way. :smile:
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