1. The problem statement, all variables and given/known data dy/dx + y*cos(x) = 3*cos(x) . Find the particular solution of the differential equation dy/dx + y*cos(x) = 3*cos(x) satisfying the initial condition y(0)=5. y(x) = ________________________ 2. Relevant equations 3. The attempt at a solution I thought I had done it the right way, but my computer based homework system disagreed. Heres my work: p(t)=cos(x) g(t)=3cos(x) m: mu m(t)=exp [int] cos(x)dx m(t)= e^sin(x) then, e^sinx(y)= [int]3cosx(e^sinx)dx [int]3cosx(e^sinx)dx= 3(e^sinx)+C then to solve for y, y= 3(e^sin(x)+C)/(e^sin(x)) using the intial value to solve for C, [[the initial value was y(0)=5]] 5=3(e+C)/e 5e=3e + C<<<right here is it C or 3c?>> c=2e and plugging it back into the y-equation, I get y=(3(e^sinx)+2e)/(e^sinx) Where have I gone wrong? My homework system says this is wrong... Any help would be greatly appreciated. Thank you for looking.