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zhenyazh
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hi,
the question is in the image attached.
i just don't get the correct answer.
what i did was count the total torque in respect to the pivot and equal it to i*alfa.
maybe i am getting the signs and direction wrong or maybe i am misplacing the masses.
can some one please write the equation so i could compare?

thanks
 

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this is exactly the point.
i know what i should write. but i guess i may be making a mistakes with the minuses or pluses
or with the sizes of angles...
this is why it could be great to see how it should be and from that understand where i was wrong
 
zhenyazh said:
this is exactly the point.
i know what i should write. but i guess i may be making a mistakes with the minuses or pluses
or with the sizes of angles...
this is why it could be great to see how it should be and from that understand where i was wrong

Draw the rod at the angle of 51.1 and then find the perpendicular distance of the force from the pivot point. Multiply those two and then you can equate that to [itex]I \alpha[/itex]