Need help solving tension problem.

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To solve the tension problem, it is established that segments AC and BC of cable ACB must be equal. The maximum allowable tension in the cable is 870 N, leading to the equations of motion for the forces at point C. By applying the principles of equilibrium, the angle θ is calculated to be 43.6 degrees. The height h is determined using the sine function, resulting in a height of 2.61 m. Consequently, the minimum length of the cable required to support the load without exceeding the tension limit is 5.22 m.
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Knowing that portions AC and BC of cable ACB must be equal, determine the shortest length of cable that can be used to support the load shown if the tension in the cable is not to exceed 870 N.

i attached the picture that came with the problem.

i am lost and not sure how to approach the problem.
 

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Hi X8V,

X8V said:
Knowing that portions AC and BC of cable ACB must be equal, determine the shortest length of cable that can be used to support the load shown if the tension in the cable is not to exceed 870 N.

i attached the picture that came with the problem.

i am lost and not sure how to approach the problem.

Try drawing a force diagram for the point C. What does that give you?
 
I think i figured it out. Here's what I did.

T'=1200 N
T=T

Fx = - Tcosθ + Tcosθ = 0
Fy = Tsinθ + Tsinθ - 1200N = 0

2Tsinθ = 1200N
2(870N)sinθ = 1200N
(1740N)sinθ = 1200N
sinθ = 1200N / 1740N
θ = 43.6 degrees

h = 1.8m / sin43.6
h = 2.61m

5.22m is the minimum length the cable can achieve when T=870N
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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