Need help transforming a Differential Equation

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SUMMARY

The discussion focuses on transforming the second-order differential equation \(2y'' + 3y' - 4ty = 1 - t^3\) into a first-order system in normal form and matrix notation. The user successfully divided the equation by 2, resulting in \(y'' - \frac{3}{2}y' - 2ty = \frac{1 - t^3}{2}\). The correct approach involves defining \(u = y'\), leading to two first-order equations: \(u' + \frac{3}{2}u - 2y = \frac{1 - t^3}{2}\) and \(y' = u\).

PREREQUISITES
  • Understanding of second-order differential equations
  • Knowledge of first-order systems and normal form
  • Familiarity with matrix notation for systems of equations
  • Basic calculus concepts, including derivatives
NEXT STEPS
  • Study the method for converting second-order differential equations to first-order systems
  • Learn about matrix representation of differential equations
  • Explore the existence and uniqueness theorem for differential equations
  • Investigate numerical methods for solving first-order systems, such as Euler's method
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Students studying differential equations, mathematicians working on system dynamics, and educators teaching advanced calculus concepts.

bengaltiger14
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Homework Statement




Express the DE as a first order system normal form. Then, express is matrix notation.

2y''+3y'-4ty=1-t^3

I need to transform this into a first order system. I first divided the entire equation by 2 and got

y''-(3/2)y'-2ty=(1-t^3)/2

I am not sure what to do now.

My first attempt was setting x1=y, x1'=y', and x2=y', x2'=y''

I don't know if I am heading in the right direction and if so, was not sure what to do next.
 
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That can be done in a number of ways. The simplest is : Define u= y' so that y"= u' and your second order differential equation becomes a first order equation in y and u. You now have two first order equations.
 
So, when I rewrite the equation, do I leave out the 'y' in the term 2ty?

hence,
u'+(3/2)u-2=(1-t^3)/2
 

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