MHB Need help understanding phase shift in trigonometric curves

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The discussion centers on determining the value of α that aligns the trigonometric curves y=asin(2π/λ(x+α)) and z=asin(2π/λx) in phase. The original poster's answer booklet states α=1−λx+nλ, while they consistently arrive at α=nλ, where n is an integer. Participants confirm that both curves have a period of λ, indicating they will be in phase when α equals kλ, with k being any integer. Clarification on the correct interpretation of the equations and phase alignment is sought. The conversation emphasizes the importance of understanding phase shifts in sinusoidal functions.
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At what value of α is the curve y=asin2π/λ (x+α) in phase with z=asin2π/λ(x)?

My answer booklet says α=1−λx+nλ, but I keep getting α=nλ, where n=0,1,2...
I have no clue how to get to the answer shown in the mark scheme. Any insight would be much appreciated!
 
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Guessing at your syntax ... are the following interpretations correct?

$y = A\sin\left[\dfrac{2\pi}{\lambda} \cdot (x + \alpha)\right]$

$z = A\sin\left(\dfrac{2\pi}{\lambda} \cdot x \right)$

If so, then the period of both sinusoids is $\lambda$, hence I agree that the two will be in phase for $\alpha = k \lambda \, , \, k \in \mathbb{Z}$
 
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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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