Need help understanding phase shift in trigonometric curves

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SUMMARY

The discussion centers on determining the phase shift α in the trigonometric curves defined by the equations y = A sin(2π/λ (x + α)) and z = A sin(2π/λ x). The correct value of α for the curves to be in phase is α = nλ, where n is an integer (n = 0, 1, 2, ...). However, the answer booklet suggests α = 1 - λx + nλ, which is incorrect based on the established periodicity of the sine function. The participants confirm that both curves share a period of λ, leading to the conclusion that they are in phase when α equals kλ for any integer k.

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At what value of α is the curve y=asin2π/λ (x+α) in phase with z=asin2π/λ(x)?

My answer booklet says α=1−λx+nλ, but I keep getting α=nλ, where n=0,1,2...
I have no clue how to get to the answer shown in the mark scheme. Any insight would be much appreciated!
 
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Guessing at your syntax ... are the following interpretations correct?

$y = A\sin\left[\dfrac{2\pi}{\lambda} \cdot (x + \alpha)\right]$

$z = A\sin\left(\dfrac{2\pi}{\lambda} \cdot x \right)$

If so, then the period of both sinusoids is $\lambda$, hence I agree that the two will be in phase for $\alpha = k \lambda \, , \, k \in \mathbb{Z}$
 
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