Understanding Phase Shift in Trigonometric Functions

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Homework Help Overview

The discussion revolves around understanding the phase shift in trigonometric functions, specifically sine and cosine functions. The original poster presents examples involving the functions Y=-5sin(x-π/2) and y=4cos(x+π/2), seeking clarification on the direction of the phase shifts based on the signs of the parameters involved.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the relationship between the sign of the phase shift parameter and the direction of the shift. They express confusion about why a positive phase shift results in a shift to the right, while a negative phase shift indicates a shift to the left. They also question the implications of their book's definitions.

Discussion Status

Some participants engage with the original poster's questions, suggesting that the definitions provided in the book may clarify the confusion. There is an acknowledgment of the mathematical properties involved, but no consensus has been reached regarding the interpretation of the phase shifts.

Contextual Notes

The discussion references specific examples from the original poster's textbook, which may contain definitions or rules that are under scrutiny. The original poster expresses a desire for a deeper understanding to aid long-term retention of the concepts.

smashbrohamme
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Find the phase shift of a function.

Y=-5sin(x-pie/2)

The Phase shift is (pie/2)/1 which equals to pie/2. The correct answer is units to the right though..which is where I need clarification on.

My book said if phi is less than 0, it is too the left.. being -pie/2 wouldn't this indicate to the left?

Another example.

y=4cos(x+pie/2) once again phase shift is pie/2...but it is units to the left...units to left indicates phi...which is pie in this case..is negative...how is that possible?

It is easy to remember if it has a plus sign..it is units to the left...
negative sign ends up being units to the right...I just don't understand and if I don't truly understand than I won't remember it long term.

Thanks for your help.





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The Attempt at a Solution

 
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smashbrohamme said:
Find the phase shift of a function.

Y=-5sin(x-pie/2)

The Phase shift is (pie/2)/1 which equals to pie/2. The correct answer is units to the right though..which is where I need clarification on.

My book said if phi is less than 0, it is too the left.. being -pie/2 wouldn't this indicate to the left?

Another example.

y=4cos(x+pie/2) once again phase shift is pie/2...but it is units to the left...units to left indicates phi...which is pie in this case..is negative...how is that possible?

It is easy to remember if it has a plus sign..it is units to the left...
negative sign ends up being units to the right...I just don't understand and if I don't truly understand than I won't remember it long term.

Thanks for your help.
Does your book say something like:
For
\sin(x-\phi)\,,​
if \phi is positive then the shift is to the right,

if \phi is negative then the shift is to the left .​

?

If that's the case, then your \phi is π/2, which is positive.
 
ah, so they are factoring in that your equation sin(w-phi) can make two negatives into a positive...
 
smashbrohamme said:
ah, so they are factoring in that your equation sin(w-phi) can make two negatives into a positive...

Yes.
 

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