Need help with a Slope problem

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Homework Help Overview

The discussion revolves around a physics problem involving forces acting on a plane traveling at a constant velocity at an angle of 30 degrees above the horizontal. The original poster seeks to determine the lift force and resistance force while adhering to specific constraints regarding the coordinate system.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to set up equations based on the forces in the x and y directions but expresses confusion over the number of variables involved. They question the relationship between the resistance force in the y direction and the weight of the plane.
  • Some participants clarify the definitions of lift and resistance, noting their orientations relative to the motion of the plane.
  • Others suggest using trigonometric functions to resolve forces that are not aligned with the axes.

Discussion Status

The discussion includes clarifications about the definitions of lift and drag, with some participants providing external resources for further understanding. There is acknowledgment of the original poster's struggle with the coordinate system, and some guidance has been offered regarding the relationships between the forces. However, explicit consensus on the approach to the problem has not been reached.

Contextual Notes

The original poster is constrained by the requirement not to shift the Cartesian coordinate system, which complicates their ability to resolve the forces directly. There is also a mention of the need to balance forces for constant velocity, which adds to the complexity of the problem.

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Need urgent help with a Slope problem

Homework Statement


A plane is traveling at a constant velocity at 30 degrees above the horizontal. Weight (W)=86 500 N; thrust (T)=103 000 N. Find the lift force and the resistance force (L= normal force, R=friction) without shifting the cartesian coordinate system


Homework Equations


sum of the forces in the x=ma, sum of the forces in the y=ma. a=0.


The Attempt at a Solution


I have set up the problem with x dir: T cos(30) - L sin(30) - Rcos(30)=ma and y dir: W - T sin(30) + L cos(30) - R sin(30)=ma and ma=0. R in the y dir is negative. Is R in the y dir equivalent to mg? I'm stuck with too many variables in my equation. Any help would be greatly appreciated.
 
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W = mg and it acts directly downward. Lift acts vertically. Resistance (Drag) acts in opposition to motion, or against the thrust.

See - http://www.grc.nasa.gov/WWW/K-12/airplane/forces.html

http://www.grc.nasa.gov/WWW/K-12/airplane/presar.html
Since the fluid is in motion, we can define a flow direction along the motion. The component of the net force perpendicular (or normal) to the flow direction is called the lift; the component of the net force along the flow direction is called the drag. These are definitions. In reality, there is a single, net, integrated force caused by the pressure variations along a body. This aerodynamic force acts through the average location of the pressure variation which is called the center of pressure.

By convention take T and L to be positive, and R and W (= mg) to be negative.

See also - http://www.grc.nasa.gov/WWW/K-12/airplane/cruise.html
which gives the condition for straight (horizontal) flight.
 
I understand the concepts as you explained them. My problem is that I connot tilt the x,y axis to solve the problem with information I have. Therefore, I am trying to use trig functions to solve for T and R, which are not directly on the x and y axis. The only compnent that is on the x and y-axis is W. Since R in the y direction is negative, can I use mg to solve R (in the y direction) sin (30)?
 
Anyone?
 
What does the text say about lift (L). According to NASA's site, L is vertical and balance against weight. The thrust (T) and drag or resistance (R) are oriented along the axis of the aircraft.

So that would imply L = W and T = R for cruising or constant velocity.
 
Thank you! That is exactly the information I needed! The problem worked out great.
 

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