Need help with a triangle's length side/ angle relation.

Click For Summary
The discussion centers on understanding the equation x = sin(theta) presented in a video. The user questions the derivation of this equation, specifically regarding the relationship between the sine of theta and the sides of a triangle. It is clarified that sine of theta is indeed defined as the opposite side (x) over the hypotenuse. The hypotenuse in this context is identified as the length of the pendulum arm, which is 1. This reinforces the connection between the angle and the triangle's dimensions in the scenario discussed.
Dyatlov
Messages
25
Reaction score
1
Hello.
I am trying to wrap my head around where from did he got the x = sin of theta equation at the 32:44 mark of the video: .
Isn't sine of theta x over the hypotenuse in the diagram ?
Thanks in advance!
 
Mathematics news on Phys.org
Dyatlov said:
Isn't sine of theta x over the hypotenuse in the diagram ?
Yes it is, and the length of the hypotenuse (=the pendulum arm) seems to be 1.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

Similar threads

  • · Replies 38 ·
2
Replies
38
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
1K
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K