Need help with a Very Hard Kinematics Qn

[physicsnoob93]

Homework Statement

Imagine a tank traveling at constant speed v1 along direction AB and a missile is chasing the tank with constant speed v2. The direction of motion of the missile is always pointing toward the tank. At the t the tank is at position F and the missile is at position D, where FD is perpendicular to AB and FD = L. What is the acceleration of the missile at this instant?

A---------------F---------------B
************|
************|
************|
************|
************D

I have no clue, i have spent hours on this qn. I tried drawing the initial and final velocity vectors for the missile but i have no idea how to continue from there.

Thanks if anyone can help.

Homework Equations

?

The Attempt at a Solution

 

[chrisk]

Acceleration is a change in velocity with respect to time. The missle velocity relative to the tank is v2 - v1. There is no linear acceleration in this problem. Are you trying to solve for the angular acceleration?

 

[Thaakisfox]

Its best to use relative coordinates.
Lets fix our system to the tank, and use polar coordinates, so r will be the instantaneous distance between the missile and the tank, and \phi will be the angle between this and the initial position.
Our equations are then:

$$\dot r=v_2-v_1\sin\varphi$$

and

$$r\dot\varphi=v_1\cos\varphi$$

Now we know that the acceleration in polar coordinates is:

$$\vec a = (\ddot r -r\dot\varphi^2)\vec e_{r} + (2\dot r\dot\varphi + r\ddot\varphi)\vec e_{\varphi}$$

Using the equations, calculate the acceleration, and after you are done put $$\varphi=0$$ and r=L, and you will get it at the beginning.

It turns out to be:

$$a=\frac{v_1v_2}{L}$$

(I be wrong, because I just scribbled it up quickly... :D)

 

[physicsnoob93]

Thanks for the replies. I solved it using similar triangles and i got v1v2/L too.

My Solution is:

If there's a triangle drawn for the distance,

there's the adjacent with l and the opposite to be V1*dt

If there's a triangle for velocity,
The adjacent is V2, the opposite is a*dt
Then we get

V1dt/l = adt/V2
Simplifying,
a = V1V2/l

Thanks though :D