Need help with confirming if this 555 timer circuit with transistor will work?

Click For Summary
The discussion revolves around the feasibility of using a 555 timer and a 2N2222 transistor to supply 450-600 mA for a personal project. The user has successfully generated a square wave output but is concerned about the current limitations of the 555 timer, which can only provide 200 mA. Suggestions include using the transistor in common emitter mode, but there are warnings about potential phase issues that could prevent effective current flow. Additionally, it is advised to consider a more robust power transistor to handle the required current without overheating. Overall, the circuit may work with adjustments, but careful consideration of component specifications is necessary.
SF49ER
Messages
2
Reaction score
0
I am an electrical engineer student at SIU and I'm working on an personal project where I am trying to use the following items to supply current between 450-600 mA:

555 timer
2N2222 transistor
4 AA batteries in series for 6V
Resistors and capacitors on 555 timer while just resistors on transistor

I set up the circuit to have the 4 AA batteries supply 6 volts to the 555 timer. With a couple of resistors, and capacitors i have a square wave output with about 400 ms on and 300 ms off. I wanted to use the timer to supply the 400 mA but it could only send 200mA max so i decided to put an transistor (2N2222) on the output of the 555 timer with an resistor to reduce the current to the base. I also ran the emitter to the ground.My question is that if I also ran the output of the timer (around 5V) so that when the timer is on this output will supply voltage to two small value resistors in parallel and use the current from those to supply the needed current to my ouput that requires the value.

I tried this as well in multisim and I got the current that i needed confirmed by connecting a multimeter in series with the collector of the transistor.

So, i wanted to know if this circuit would actually work if i built it with the transistor? If not what other way could i use my timer to source another component to give me the desired current. I liked the timer because i would like to have the current needed to be turned off and on as well.

If anybody could help with this or has any advise on a better way to implement a circuit i would really appreciate it. I am new to the forum so i hope to learn some valuable information from here, while continuing to learn about ee :)... Have a nice day everyone
 
Engineering news on Phys.org
To use the 2N2222 transistor as an open collector output, (as you stated) tie the emitter to ground, and supply it with ~20 mA base current. Because the NE555 output doesn't completely go to ground when it is low, use a separate equal resistor tied between the NE555 output and ground as a pull down. The NE555 should be able to source 40 mA. The 2N2222 avg power dissipation will be close to the max dissipation limit, and the VCE sat at 500 mA is ~1 volt, so you might substitute an npn with a TO-220 case.
Bob S
 
Just to be sure, would you like to draw up your circuit and post it? Just a screen grab from your simulator would be OK. (Push PrtSc on your keyboard and then paste it into MS Paint)

It sounds like there is a problem doing what you ask.

If you have a 555 driving a transistor in common emitter mode, there will be a phase problem with using both the 555 and the transistor to supply your current.

See attached diagram. If you have something like this, the transistor will conduct when the 555 output is high.
But if you connect it as in the second diagram, current will only flow in the red wire from the load if the 555 output is low.
So, the output from the 555 will not assist with giving you extra current in the load when you need it, but it will make the transistor hotter when the 555 output is high.

As BobS suggests, you would need to get a power transistor that could easily produce the sort of currents you need. These can be mounted on a piece of metal used as a heatsink so the transistor doesn't get too hot.
 

Attachments

  • 555 output.PNG
    555 output.PNG
    4.4 KB · Views: 595
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

Similar threads

Replies
16
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
1
Views
2K
  • · Replies 58 ·
2
Replies
58
Views
11K
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
11K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K