Surface area of sin(x) revolved about the x-axis from 0 to π/4

[physics=world]

1. Use the integration capabilities of a graphing utility to approximate the surface area of the solid of revolution. (Round your answer to four decimal places.)

Function:
y = sin(x)

Interval:
[0, pi/4]


revolved about the x-axis



2. Use the area of a surface of revolution equation



3. This was plug into the formula sin(x) sqrt(1+cos(x)^2)

than i integrated it , and it became a mess.

can anybody help me solve this, or even with a ti calculator if possible?

 

[SteamKing]

Show your work.