Need help with fluids and pressure problem

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SUMMARY

The discussion focuses on calculating the force exerted by water on two faces of an L-shaped tank, specifically face A and face B. The correct approach involves using the equation F = PA, where pressure (P) is determined by the depth of water (d). The user initially calculated the force incorrectly as 2.85x10^6 N but later corrected it to 1.25E6 N by integrating the pressure over the height of the wall, acknowledging that atmospheric pressure should not be added to the force on face A.

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[SOLVED] need help with fluids and pressure problem

Homework Statement


The L-shaped tank shown below is filled with water and is open at the top.
(a) If d = 4.0 m, what is the force on face A due to the water?
N (up)

(b) What is the force on face B due to the water?
N (right)
hrw7_14-33.gif


Homework Equations


F=PA


The Attempt at a Solution


Fa=PaAa+Patmosphere
Pa=pgHa
Ha=2d
Fa=pg2d^3+Patmosphere
d=4
I got 2.85x10^6N but that was wrong
I was given this hint when i got it wrong:Can you find the pressure at a given depth? How is force related to pressure for a given horizontal surface area? On the vertical wall, how does pressure vary with depth along the wall? Do you see that you need to first consider a strip that has the wall's width but only a differential height dy? What is the force on the strip? Do you see that you next must integrate to find the force on the full wall (all the horizontal strips)?
is this how it should be done:
Fa=Integral(pgd^2 dy)+Patmosphere
 
Last edited:
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(a) If d = 4.0 m, what is the force on face A due to the water?
N (up)
i was not suppose to add the Patmosphere
Fa=1.25E6N
 

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