Need help with Integral: e^(-1/x)?

[Alexx1]

Can someone help me with this integral?

e^(-1/x)

 

[CFDFEAGURU]

Just follow the rules for exponential integration.

$$\int$$ $$e^{u}$$ du = $$e^{u}$$ + C

Thanks
Matt

 

[Mark44]

If this is the integral:
$$\int e^{-1/x}dx$$

an ordinary substitution is not much help. Alexx1, can you show us the complete integral you're trying to do?

 

[HallsofIvy]

Just follow the rules for exponential integration.

$$\int$$ $$e^{u}$$ du = $$e^{u}$$ + C

Thanks
Matt

If the problem were $\int e^u du$, but it isn't and there is no good way to change it to that form.

It looks to me like $\int e^{1/x} dx$ does not have an anti-derivative in terms of elementary functions.

 

[g_edgar]

in terms of an exponential integral function...

$\int \!{{\rm e}^{-{x}^{-1}}}{dx}=x{{\rm e}^{-{x}^{-1}}}-{\rm Ei}_1<br /> \left({x}^{-1} \right) <br />$

 

[CFDFEAGURU]

HallsofIvy,

Yes, now I see that a simple substitution is not the way to proceed. Thanks for correcting me.

Thanks
Matt