1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Writing impulse in vector notation

  1. Apr 29, 2013 #1
    1. The problem statement, all variables and given/known data
    A baseball strikes a bat. It's moving at 40m/s to the left horizontally. When it hits the bat it leaves at 60m/s with an angle of 30 degrees to the horizontal. The mass of the ball is 0.25kg.


    2. Relevant equations
    P(momentum)=mv
    Pf-Pi=ΔP
    ΔP=J(impulse)

    3. The attempt at a solution

    Since we are speaking in vector terms I would assume that 60 should be negative. But anyways the question asks to write the net impulse in vector notation. It reads it as J=Jxi + Jyj. Since change in momentum(delta P) is equal to impulse; If I was trying to find the impulse in each direction like the question asks, how could I do it?

    I was thinking I could do:

    the impulse for the x-direction should be: (0.25)(-60cos30) - (0.25)(40cos0)
    the impulse for the y-direction should be: (0.25)(-60sin30) - (0.25)(-60sin0)

    I ended up with: J=-26i -7.5j

    Is this correct?

    Thank you very much!!
     
  2. jcsd
  3. Apr 29, 2013 #2

    haruspex

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    I will assume the 30 degrees is above horizontal.
    It's not that the 60m/s should be read as -60 (which affects both horizontal and vertical), but that the 30 degrees should be read as 150 degrees in relation to the initial velocity. Note that this makes the vertical change positive, as it should be.
     
  4. Apr 29, 2013 #3
    If home plate is the origin, and the horizontal direction away from home plate is the positive x-direction, and the upward direction is the positive y-direction, then then

    initial x momentum = -(0.25)(40)
    initial y momentum = 0

    final x-momentum = +(0.25)(60 cos(30))
    final y-momentum = +(0.25)(60 sin(30))

    Impulse of force = change in momentum = (final momentum) - (initial momentum)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Writing impulse in vector notation
  1. Vectors notations. (Replies: 3)

  2. Vector notation (Replies: 3)

Loading...