1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Need Help with My Limit Homework

  1. Sep 22, 2009 #1
    1. The problem statement, all variables and given/known data
    Limit x approached zero from right which is X * [|1/X|]

    2. Relevant equations
    Since i Don't know how to draw the graphs, then i don't have an equations


    3. The attempt at a solution
    I've tried to drew the graphic, but from the graphs, i've concluded that lim x aprroached zero from right [|1/x|] does not exist because 1/0 = undefined.

    Actually, the answer is 1, but still i don't know how to solve this.
    So, guys, please help me up!Thanks
     
  2. jcsd
  3. Sep 22, 2009 #2

    VietDao29

    User Avatar
    Homework Helper

    Is this your limit:

    [tex]\lim_{x \rightarrow 0 ^ {+}} \left( x \left| \frac{1}{x} \right| \right)[/tex]?

    Well, the first thing when dealing with absolute value, is to take out all absolute signs.

    You know that:

    [tex]|a| = \left\{ \begin{array}{ll} a & \mbox{, if } a \geq 0 \\ -a & \mbox{, if } a < 0 \end{array} \right.[/tex]

    So, when x tends to 0+, (i.e it tends to 0 from the right), is 1/x positive or negative? Can you break absolute signs?

    After breaking (taking out) all the absolute signs, you should be arriving to the final answer shortly. :)
     
  4. Sep 23, 2009 #3
    Whoops, i'm sorry for misunderstanding, looks like [| |] is not dealing with Greatest INteger Function. Then, what i mean with [|x|] is [[ x ]], sorry..
     
  5. Sep 23, 2009 #4

    VietDao29

    User Avatar
    Homework Helper

    You mean the http://en.wikipedia.org/wiki/Floor_and_ceiling_functions" [Broken], right? Or are you refering to the Floor Function?

    [tex]\lim_{x \rightarrow 0 ^ {+}} \left( x \left\lceil \frac{1}{x} \right\rceil \right)[/tex]

    If you really mean the Ceiling Function, then from its definition, we can derive to the following inequality:

    [tex]\frac{1}{x} \leq \left\lceil \frac{1}{x} \right\rceil \leq \frac{1}{x} + 1[/tex]

    Can you find the limit of the expression based on this inequality?
     
    Last edited by a moderator: May 4, 2017
  6. Sep 23, 2009 #5
    I've always known [|x|] to be the greatest integer function, or floor function.
    Are you saying it actually looks like [[x]] instead?
     
  7. Sep 24, 2009 #6
    Yeah, i mean it's the ceiling function. Thanks a lot, right now it could be derived.Actually i got this problems from Purcell's Calculus Book, do u have one on you??
     
    Last edited by a moderator: May 4, 2017
  8. Sep 26, 2009 #7
    what is the answer?
     
  9. Sep 26, 2009 #8
    Use the Squeeze Theorem on the inequality in post #4.
     
  10. Sep 26, 2009 #9
    the interval between 1/x and 1/x + 1 is fairly large though?
     
  11. Sep 26, 2009 #10
    Multiply through by x, then take the limit of each expression. Remember that x is not zero; the limit only examines the behavior of these expressions in arbitrarily small neighborhoods of 0. Use the Squeeze Theorem to imply the limit of the central expression.
     
  12. Sep 26, 2009 #11
    right, thanks
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Need Help with My Limit Homework
  1. Homework Need Help (Replies: 1)

Loading...