- #1

eadel

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## Homework Statement

An 8g bullet is fired into a 250g block that is initially at rest at the edge of a table of height 1m. The bullet remains in the block, and after the impact the block lands 2m from the bottom of the table. Determine the initial speed of the bullet. [To clarify, the block, after getting hit by the bullet, gets knocked off a 1m tall table and lands 2m away from where it started. no friction either.]

## Homework Equations

m1v1i + m2v2i = m1v1f + m2v2f

p=mv

## The Attempt at a Solution

before the collision, i have...

m1v1i + m2v2i = (m1+m2)vf

plug in the data...

(0.008)vi + 0 = (0.258)vf

and that's where I'm stumped. I tried using delta-y=v0*t + 1/2at^2 to solve for t and then plug into solve for the velocity in the x direction... (v=d/t)... and then using that as my vf to solve for my vi... and even though the answer LOOKED right (143 m/s) i got the strange feeling it was wrong. any suggestions or leads guys?