Need help with projectiles initial velocity using height and distance

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SUMMARY

The discussion centers on calculating the initial velocity of a projectile, specifically a baseball, that traveled 180 meters horizontally and reached a height of 21.3 meters. The user applied the kinematic equation \( u^2 = v^2 - 2as \) to derive the initial velocity (u) as 59.9 m/s, with final velocity (v) set to 0, distance (s) as 180 meters, and acceleration (a) as -9.8 m/s² (gravity). The user questioned the appropriateness of the equation and whether the angle of projection should be considered, indicating a need for clarification on projectile motion concepts.

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  • Understanding of kinematic equations in physics
  • Knowledge of projectile motion principles
  • Familiarity with gravitational acceleration (g = -9.8 m/s²)
  • Basic algebra for solving equations
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batcave1985
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home run that was estimated to have
landed 180 metres from the home plate and to have reached a
height of 21.3 metres. Calculate the initial velocity of the
ball.

u^2=v^2-2as

t=?
u=?
v=0
s=180
a=g= -9.8

u^2= √0^2-2x-9.8x180
u= 59.9 m/s


am I using the right equation for this problem. I am not sure if I have to find the angle using the height and the range of the ball to help find the initial velocity. just want to know if this is the right direction with this problem
 
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What are u and v? What is s? And why do you not use the maximum height? Does the ball move horizontally? If so, is g the horizontal acceleration? Does not accelerate Earth the objects vertically?

ehild
 

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