Need Help With Quadrilateral Calculations: LN and KM Angles

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Homework Help Overview

The discussion revolves around calculating the angles that the lines LN and KM make with the x-axis in a quadrilateral defined by the vertices K(-2, 7), L(8, 7), M(14, -1), and N(4, -1). The original poster is attempting to apply mathematical concepts related to slopes and angles but is encountering difficulties with the second line, KM.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster describes calculating the slope of line LN and using the inverse tangent function to find the angle, which they believe is correct. They express uncertainty regarding the calculation for line KM and question whether the negative slope affects the angle calculation.

Discussion Status

Participants are actively engaging with the problem, with one suggesting that the negative angle obtained from the slope of KM should be adjusted by subtracting from 180 degrees. There is a recognition of the need to consider how the problem is worded, indicating a productive exploration of different interpretations.

Contextual Notes

Participants note the potential variability in how angle measurements are interpreted based on the problem's wording, highlighting the importance of understanding the context of the question.

sunny304
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Hey guys, not touched any mathematics in almost 5 years and I am just getting back into it, been going well so far but hit a hurdle with this, I presume its some gaps in my knowledge.

So been at this for about an hour, got the first one, no clue on the second, can anyone offer assistance?K(-2, 7), L(8, 7), M(14, -1), N(4, -1) are the vertices of a quadrilateral.

Calculate the angle that the lines LN and KM make with the x-axis.

For LN I worked out the gradient/slope of the line and used the inverse of tan to come to the solution 63.4 which seems to be correct. However with KM employing the same method doesn't produce the correct result.

Thanks for any help.
 
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sunny304 said:
Hey guys, not touched any mathematics in almost 5 years and I am just getting back into it, been going well so far but hit a hurdle with this, I presume its some gaps in my knowledge.

So been at this for about an hour, got the first one, no clue on the second, can anyone offer assistance?


K(-2, 7), L(8, 7), M(14, -1), N(4, -1) are the vertices of a quadrilateral.

Calculate the angle that the lines LN and KM make with the x-axis.

For LN I worked out the gradient/slope of the line and used the inverse of tan to come to the solution 63.4 which seems to be correct. However with KM employing the same method doesn't produce the correct result.

Thanks for any help.

For KM, the slope is just negative, right? That will give you a negative theta when you use the tan^-1 function. What value did you get?
 
Ah its just clicked, the x-axis can't be more than 180 degrees, so when I get the negative theta, I just subtract from 180 to get the angle. So Simple.

Thank you
 
sunny304 said:
Ah its just clicked, the x-axis can't be more than 180 degrees, so when I get the negative theta, I just subtract from 180 to get the angle. So Simple.

Thank you

Yes, but be careful to look at what the problem question is -- it can vary depending on the question. Sometimes they will want the negative angle as the answer. Other times they will want you to subtract the angle from 180. Just depends on how the question is worded.
 

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