Can someone please show/explain to me the steps between the 2 circled formulas on the attached page #582 from Riley, Hobson, Bence - Mathematical Methods for Physics and Engineering 3rd edition.
We can write the recurrence relation as [itex]K_l = \frac{2l}{2l+1} K_{l-1}[/itex].
We get the formula on the left-hand side when we substitute [itex]K_{l-1}[/itex] with [itex]K_{l-1} = \frac{2l-1}{2(l-1)+1} K_{l-1-1}[/itex].
We can repeat this process until we get to [itex]l = 1[/itex] and [itex]K_0[/itex] (because of the assumption just below the grey box).
The part most on the right of the circle below is a compact way to write this product.
Thank you!
Could you please explain where does the 2nd ## 2^l l! ## term in ## 2^l l! \frac{2^l l!}{(2l+1)!} 2 ## in the lower circle come from? It has two ## 2^l l! ## terms in the numerator.
I don't know exactly how they arrive at that expression, but it could be due to some conversion that is related to the double factorial.
See: https://en.wikipedia.org/wiki/Double_factorial