Need Help with Rotational & Transitional Equilibrium LA

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To calculate torque and normal force in a rotational equilibrium lab, first identify the forces acting on the meter stick. Torque is determined by the equation Torque = Force × Length, where the force is the weight of the masses and the length is the distance from the fulcrum. Normal force typically equals the gravitational force acting on the object, but it can differ in scenarios involving additional forces or angles. In this case, the normal force can be considered equal to the weight of the meter stick plus the weights of the masses when in equilibrium. Understanding these principles will help in completing the lab effectively.
mahdi12572
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I need some help with physics...Honestly, I'm a bit slow in the class and it's killing my GPA

How do I calculate torque and normal force?

I'm working on a lab. Basically, I'm balancing a meter stick with two different mass on both sides sides with a fulcrum in between them. I need to determine the normal force and torque.

Given:
Measured mass of meter stick: .09495 kg
Location of meter stick's center of mass: 50.5m

Trial 1:
Left of Fulcrum
mass1 [kg]: .250kg
F1:?
Length 1[m]: .150m
Torque1=Force1(Length1) [Nm]:?

Right of Fulcrum
mass2 [kg]: 100kg
F2:?
Length2 [m]: .37m
Torque2= Force2(Length 2)

Trial 2:
Left of Fulcrum...
mass1 [kg]: .300kg
F1:?
Length 1[m]: .150m
Torque1=Force2(Length2):?[Nm]

Right of Fulcrum...
mass2 [kg]: 100kg
F2:?
Length2 [m]: .445m
Torque2= Force2(Length 2):? [Nm]Btw...is normal Force= Force of gravity in this case? and when isn't normal force equal to force of gravity?

Thank You
Mahdi Chowdhury (11th grade Regular Physics)
 
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Cn anyone please help me out? This lab is due tomorrow. Plzzzzzzzz? I'm falling behind in this class
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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