Need Help with Rotational & Transitional Equilibrium LA

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SUMMARY

This discussion focuses on calculating torque and normal force in a physics lab involving a meter stick balanced on a fulcrum with varying masses on either side. The user, Mahdi Chowdhury, provides specific measurements including a meter stick mass of 0.09495 kg and various trial setups with masses of 0.250 kg and 0.300 kg on the left and 100 kg on the right. Key calculations involve determining torque using the formula Torque = Force × Length, and clarifying the relationship between normal force and gravitational force in different scenarios.

PREREQUISITES
  • Understanding of basic physics concepts such as torque and normal force
  • Familiarity with the formula Torque = Force × Length
  • Knowledge of mass and weight relationships in physics
  • Ability to perform calculations involving forces and lever systems
NEXT STEPS
  • Learn how to calculate torque in various scenarios using different masses
  • Research the concept of normal force and its variations in different physical contexts
  • Study the principles of rotational equilibrium and how they apply to lever systems
  • Explore practical applications of torque in engineering and physics experiments
USEFUL FOR

High school physics students, educators teaching mechanics, and anyone seeking to understand the principles of torque and equilibrium in physical systems.

mahdi12572
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I need some help with physics...Honestly, I'm a bit slow in the class and it's killing my GPA

How do I calculate torque and normal force?

I'm working on a lab. Basically, I'm balancing a meter stick with two different mass on both sides sides with a fulcrum in between them. I need to determine the normal force and torque.

Given:
Measured mass of meter stick: .09495 kg
Location of meter stick's center of mass: 50.5m

Trial 1:
Left of Fulcrum
mass1 [kg]: .250kg
F1:?
Length 1[m]: .150m
Torque1=Force1(Length1) [Nm]:?

Right of Fulcrum
mass2 [kg]: 100kg
F2:?
Length2 [m]: .37m
Torque2= Force2(Length 2)

Trial 2:
Left of Fulcrum...
mass1 [kg]: .300kg
F1:?
Length 1[m]: .150m
Torque1=Force2(Length2):?[Nm]

Right of Fulcrum...
mass2 [kg]: 100kg
F2:?
Length2 [m]: .445m
Torque2= Force2(Length 2):? [Nm]Btw...is normal Force= Force of gravity in this case? and when isn't normal force equal to force of gravity?

Thank You
Mahdi Chowdhury (11th grade Regular Physics)
 
Last edited:
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Cn anyone please help me out? This lab is due tomorrow. Plzzzzzzzz? I'm falling behind in this class
 

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