Need help with simple acceleration problems.

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Craig accelerated to 133.5 km/h before braking to 100 km/h in 0.9 seconds. The initial velocity is indeed 133.5 km/h, and the final velocity is 100 km/h. To calculate the distance traveled during this deceleration, the equation delta s = vi(t) + 1/2(a)t^2 can be used, assuming constant acceleration. With only the initial velocity, final velocity, and time known, the average deceleration can be calculated. Understanding these concepts is crucial for solving acceleration problems effectively.
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Here's one:

Craig got up to 133.5 km/h getting around a slower vehicle within the length of the passing lane. He then spotted a police cruiser coming around the corner and hit the brakes, slowing to 100 km/h in 0.9 seconds. How much distance did he travel in this time


So I'm pretty much confused with accleration problems and identifying intial velocity and final velocity. I kow that t=.9 secs. So is the initial velocity 133.5 km/h and final velocity is 100 km/h?

Would I first use the delta s=vi(t)+ 1/2(a)t^2 equation to find the displacement of when he slowed down?
 
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ksaechao said:
Here's one:

Craig got up to 133.5 km/h getting around a slower vehicle within the length of the passing lane. He then spotted a police cruiser coming around the corner and hit the brakes, slowing to 100 km/h in 0.9 seconds. How much distance did he travel in this time


So I'm pretty much confused with accleration problems and identifying intial velocity and final velocity. I kow that t=.9 secs. So is the initial velocity 133.5 km/h and final velocity is 100 km/h?
yes.

Would I first use the delta s=vi(t)+ 1/2(a)t^2 equation to find the displacement of when he slowed down?

to use this you need to assume that acceleration is constant. at this stage you have only 3 known variables: u, v and t. but from these you can work out the average (de)acceleration
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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