Need help with solving for t value and plugging back into equation?

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SUMMARY

The discussion focuses on solving for the time variable \( t \) in the equation \( x = 16te^{-t} \), which describes the position of an electron along the x-axis. The derivative \( x' \) is calculated as \( x' = e^{-t} - te^{-t} \). Setting \( x' = 0 \) leads to the equation \( -te^{-t} = -e^{-t} \), resulting in \( t = 1 \) as the moment when the electron momentarily stops. This solution confirms that the electron is at a distance of \( x(1) = 16 \) meters from the origin when it stops.

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1. An electron moving along the x-axis has a position given by x=16*te^-t m, where t is in seconds. How far is the electron from the origin when it momentarily stops?


2. Homework Equations
uv=u'v+uv'


3. The Attempt at a Solution
x'=e^-t - t*e^-t
e^-t - t*e^-t = 0
-te^-t = -e^-t
t = 1?
 
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hi itsgabriella! welcome to pf! :smile:

(try using the X2 button just above the Reply box :wink:)
itsgabriella said:
x'=e^-t - t*e^-t
e^-t - t*e^-t = 0
-te^-t = -e^-t
t = 1?

yup! :smile:

what's worrying you about that? :confused:
 

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