Need help with solving this hard integral

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SUMMARY

The integral \int_{-a}^{a}\sqrt{a^2-x^2}e^{i(kx-wt)}dx can be simplified using the substitution x=a\sin(u), leading to \int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}a^2\cos^2(u)e^{i(ka\sin(u)-wt)}du. The integral can be expressed as e^{-i\omega t}\int_{-a}^a \sqrt{a^2-x^2}\cos(kx)dx, where the sine term contributes nothing due to its odd function nature. The final result involves the Bessel function of the first kind, yielding e^{-i\omega t}\frac{a\pi}{k}BesselJ(1,ka), confirmed through numerical solutions in Matlab.

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m06antwe
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I have big problems solving this integration:

[tex] \int_{-a}^{a}\sqrt{a^2-x^2}e^{i(kx-wt)}dx[/tex]

I did an substitution with:

[tex] x=a*sin(u)[/tex]

Which gave me:

[tex] \int_{-{pi}/2}^{{pi}/2}a^2cos^2(u)e^{i(kasin(u)-wt)}du[/tex]

But i don't know if that did it any better, cause i can't figure out how to go on from there. I've been told to try the substitution:

[tex] v=a*sin(u)[/tex]

But without any success... Please help me somebody!
 
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m06antwe said:
I have big problems solving this integration:

[tex] \int_{-a}^{a}\sqrt{a^2-x^2}e^{i(kx-wt)}dx[/tex]

Write it as

[tex]e^{-i\omega t}\int_{-a}^a \sqrt{a^2-x^2}\cos(kx) + i\sqrt{a^2-x^2}\sin(kx))\, dx[/tex]

The second term is an odd function of x which contributes nothing to the answer. The first term isn't going to give you an elementary answer. Maple gives

[tex]e^{-i\omega t}\frac{a\pi}{k}BesselJ(1,ka)[/tex]

where BesselJ is the Bessel function of the 1st kind of index 1 with argument ka.
 
Oh, I would not have figured out that myself! I've never seen the Bessel function before, but it seems to give me the same answer when I'm solving it numerically in Matlab so therefore I'm happy!

Thanks a lot, that really helped me! :smile:
 

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