Need MORE Hmwk helpFluid mechanics, Fluids in motion, pressure

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Homework Help Overview

The discussion revolves around a fluid mechanics problem involving the flow of water through a tube that narrows at one end. The original poster seeks to determine the gauge pressure at a specific point in the tube, given the flow rate and diameters at two points.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of Bernoulli's equation and the continuity equation to relate pressures and velocities at different points in the tube. Questions arise regarding the calculation of pressure in the smaller diameter section and the relevance of gauge pressure.

Discussion Status

The conversation includes attempts to calculate pressures and velocities, with some participants providing insights into the relationships between these variables. There is acknowledgment of the need for numerical values and clarification on the concept of gauge pressure. While some progress has been made, there is no explicit consensus on the final approach or solution.

Contextual Notes

Participants note the importance of flow rate and the diameters of the tube sections, as well as the distinction between gauge pressure and absolute pressure. There is mention of potential frictional losses, although no specific data is provided to compute these effects.

LBRRIT2390
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College Physics

Homework Statement



The figure shows a section of a long tube that narrows near its open end to a diameter of 1.0mm. Water at 20celsius flows out of the open end at 0.020 L/s

What is the gauge pressure at point P, where the diameter is 4.0mm?

http://session.masteringphysics.com/problemAsset/1014234/7/jfk.Figure.P13.62.jpg

Homework Equations



Bernoulli's equation

The Attempt at a Solution



Same as my last post, no solution found yet. Please help me start and work through this problem.
 
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Bernoullis here is quite simple and the basis for a venturi tube. In the initial frame you have lower kinetic energy and some potential energy from pressure, P. Some of that potential energy is traded for kinetic energy;

P1+1/2 rho(v^2)= P2 + 1/2 rho(v'^2). V' is the final velocity. From continuity of flow, the two velocities can be expressed as a ratio. That help?
 
Thank you so much for replying!
So I plugged in everything that I calculated so far and ended up with:
P1 = P2 +49805

I can't figure out how to find the pressure in the smaller diameter tube so I can plug that in. I know it should be easy...I have the flow rate and the diameter, but I'm stuck.

Variables I've used:
rho=1000kg/m^3
Velocity1 = 0.623 m/s
Area of Larger section: 0.0126m
Velocity2= 10m/s
Area of Smaller section: 0.00785m
 
So you need a numerical answer not expressed in terms of p?

Edit: I reread the question it is asking for gauge pressure.
 
Correct, a numerical value in Pascals. I think I need to incorporate the length of each section as well, not sure how though.
 
Well gauge pressure is relative to P. No length doesn't enter it unless you have frictional losses and data to compute these. More info would be given if it were needed.
 
What do you mean by gauge pressure is relative to P?

Do you think that I am on the right track with the progress I've made? P1=P2+49806
 
LBRRIT2390 said:
What do you mean by gauge pressure is relative to P?

Do you think that I am on the right track with the progress I've made? P1=P2+49806


google gauge pressure. And yes.
 
I was not able to get the answer before my assignment was due, the answer was 8.2E5 Pa.

But thank you, I really appreciate your help.
 

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