Need some clarification in regards to trigonometry

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SUMMARY

This discussion clarifies the application of trigonometric functions, specifically sine and cosine, in resolving forces in physics problems. The key takeaway is that the component of a force in a given direction is determined by multiplying the force by the cosine of the angle between the force and that direction. Sine is used only when considering the "wrong" angle, which can lead to confusion. Understanding the relationship between angles and their respective sides in right triangles is crucial for correctly applying these functions.

PREREQUISITES
  • Basic understanding of trigonometric functions: sine and cosine
  • Familiarity with right triangles and their properties
  • Knowledge of vector components in physics
  • Ability to interpret angles in different quadrants
NEXT STEPS
  • Review the properties of right triangles and the definitions of sine and cosine
  • Study vector decomposition in physics, focusing on force components
  • Learn about the unit circle and how it relates to trigonometric functions
  • Explore the concept of angles in different quadrants and their impact on sine and cosine values
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Students studying physics, particularly those tackling problems involving forces and trigonometry, as well as educators seeking to clarify these concepts for their students.

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Need some clarification in regards to trigonometry...

Homework Statement



For some reason, I am not seeing the cause of this. In attached problem 1, the Forces of x are described with a cos while forces of y are described with sin. In the second problem, the forces of X use sin and the forces of y use cos... What am I missing here? Is there a certain topic I can review? Is it because of the quadrants they are in? the triangle they make (I would think obviously, I just don't see it :( )


Some of problem 1 has been cut off so I could attach the files

Homework Equations



How do I figure out if I'm suppose to use a cos or a sin for x or y?
 

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I can't see your images yet, but I'm going to guess the problem is which angle you are using:
Consider a right angle triangle, with sides x, y and hypotenuse 1 (draw it!). Let's take the angle t to be between the sides x and 1: then cos(t)=adjacent/hypotenuse=x
sin(t)=opposite/hypotenuse=y

But if we take s to be the angle between 1 and y
cos(s)=adjacent/hypotenuse=x
sin(s)=opposite/hypotenuse=y

Does that answer your question?
 
r6mikey said:
What am I missing here? Is there a certain topic I can review? Is it because of the quadrants they are in? the triangle they make

How do I figure out if I'm suppose to use a cos or a sin for x or y?

Hi r6mikey! :smile:

Forget about triangles.

The component in a direction is always found by multiplying by the cos of the angle between.

(so you only use sin if it's the "wrong" angle! :biggrin: )
 

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