- #1
goodOrBad
- 25
- 2
- Homework Statement
- I am given F1=2500N and F2=4000N
- Relevant Equations
- Fx=0
Fy=0
Need to find forces in S1 and S2
- Thread starter goodOrBad
- Start date
Click For Summary
The discussion focuses on determining the forces in structural members S1 and S2, specifically whether they are under compression or tension. It clarifies that both members are actually in tension due to the resultant force from F1 and F2, which is approximately 6250 N at a 40° angle. The importance of accurately representing angles in diagrams is emphasized, as inaccuracies can lead to misinterpretations of the forces involved. A method of resolving forces normally to each reaction is suggested for easier calculations, avoiding the complexity of simultaneous equations. Overall, the conversation highlights the significance of clarity in diagrams and effective problem-solving techniques in structural analysis.
- #2
Lnewqban
Homework Helper
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What is the question?
Is that symbol an S?
Do you need to tell either compression or tension are acting on members 1 and 2?
Is that symbol an S?
Do you need to tell either compression or tension are acting on members 1 and 2?
- #3
goodOrBad
- 25
- 2
To find forces in member 1 and 2 that is all, yes I just choose S as a symbol
- #4
Lnewqban
Homework Helper
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I have obtained similar results via graphical vectorial addition.
The angles in your diagram are not at scale, which gave me the initial impression that member 2 would be working in compression mode.
However, both structural members are working under tension to resist the action of resultant force from F1 and F2 combination (approximately 6250 N at 40° from horizontal).
The angles in your diagram are not at scale, which gave me the initial impression that member 2 would be working in compression mode.
However, both structural members are working under tension to resist the action of resultant force from F1 and F2 combination (approximately 6250 N at 40° from horizontal).
- #5
- 42,785
- 10,490
I confirm your answers, but it is easier if you resolve normally to each reaction force in turn. That gives you one equation to solve for each separately instead of having to solve simultaneous equations.
- #6
goodOrBad
- 25
- 2
Yeah and when I see it now I see it would have been easier to just use the angles close to the x-axis
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