Asking for help with a physical problem that uses a piston to push water

In summary, the figure shows that F is the external force oriented to the left on the outside face of the piston.
  • #36
haruspex said:
@Baluncore is saying to consider the area S as made of two areas ...
Can you think of it this way, that if you don't change the height, no matter what S2' prime does, it doesn't matter what S1' prime does, and the value of F stays the same? Is F =-ρgHS1.
 
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  • #37
vxiaoyu18 said:
I think I've figured out how to do it, and I can do it very quickly with PASCAL's law.
1. F=-ρgSH;
2. F=-(1/2)ρgSH;
3. F=-(1/2)ρgS(H1+H2);
4. F =-ρgS(H1+H2).
Thanks for the answer, and I think I'm pretty sure now that the answer is correct, which is to use PASCAL's law.
 
Last edited:
  • #38
Baluncore said:
The sign of F will depend on convention. F = - ρ⋅g⋅H⋅S1
Watch out for fires in your national forests. Be safe. Hope you get through this soon.
 

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