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## Homework Statement

An element X forms both a dicholride( XCl2) and tetrachloride(XCl4). Treatment of 10.0g of XCl2 with excess forms 12.55g of XCl4. Calculate Atomic Mass of X and Identify X

## Homework Equations

no equation needed...but urgent

## The Attempt at a Solution

i try subtracting 12.55g of XCL4 with 10.0g of 10.0g of XCL2

and i am lost at what is the EXCESS, is that CL2 ?

if it is...then i have 2.55g/ 71g CL2 = 0.359mole of CL2. basically i am lost