Need to identify mysterious element

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Homework Statement


An element X forms both a dicholride( XCl2) and tetrachloride(XCl4). Treatment of 10.0g of XCl2 with excess forms 12.55g of XCl4. Calculate Atomic Mass of X and Identify X


Homework Equations


no equation needed...but urgent


The Attempt at a Solution



i try subtracting 12.55g of XCL4 with 10.0g of 10.0g of XCL2
and i am lost at what is the EXCESS, is that CL2 ?

if it is...then i have 2.55g/ 71g CL2 = 0.359mole of CL2. basically i am lost
 
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  • #2
Do you get the equation

[tex] \frac{10}{x+71}=\frac{12.55}{x+142} [/tex] ?
 
  • #3
thank you, i never realize i just have to use cross multiply. i see ur work as x+CL2(71) = x+Cl4(142)
 

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