An element X forms both a dicholride( XCl2) and tetrachloride(XCl4). Treatment of 10.0g of XCl2 with excess forms 12.55g of XCl4. Calculate Atomic Mass of X and Identify X
no equation needed...but urgent
The Attempt at a Solution
i try subtracting 12.55g of XCL4 with 10.0g of 10.0g of XCL2
and i am lost at what is the EXCESS, is that CL2 ?
if it is...then i have 2.55g/ 71g CL2 = 0.359mole of CL2. basically i am lost