Need to identify mysterious element

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SUMMARY

The discussion revolves around calculating the atomic mass of an unknown element X that forms both dichloride (XCl2) and tetrachloride (XCl4). The user presents a scenario where 10.0g of XCl2 reacts with excess chlorine to yield 12.55g of XCl4. The key to solving the problem lies in setting up the equation based on the mass differences and using cross-multiplication to isolate the variable representing the atomic mass of element X.

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Homework Statement


An element X forms both a dicholride( XCl2) and tetrachloride(XCl4). Treatment of 10.0g of XCl2 with excess forms 12.55g of XCl4. Calculate Atomic Mass of X and Identify X


Homework Equations


no equation needed...but urgent


The Attempt at a Solution



i try subtracting 12.55g of XCL4 with 10.0g of 10.0g of XCL2
and i am lost at what is the EXCESS, is that CL2 ?

if it is...then i have 2.55g/ 71g CL2 = 0.359mole of CL2. basically i am lost
 
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Do you get the equation

[tex]\frac{10}{x+71}=\frac{12.55}{x+142}[/tex] ?
 
thank you, i never realize i just have to use cross multiply. i see ur work as x+CL2(71) = x+Cl4(142)
 

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