First time poster, site looks very informative so I thought I would make a post. This is for Mechanics class and now covering Dynamics. This is my take home problem. A basket ball player shoots when she is 5 m from the backboard. Knowing that the ball has an intial velocity Vo at an angle of 30⁰ with the horizontal, determine the value of Vo when d is equal to (a) 228 mm, (b) 420 mm. 1. The problem statement, all variables and given/known data given info: x: player is 5M from back board y: initial height of ball 2m from floor, hoop is 3.048m from floor angle: 30⁰ d: this is the distance from the back board or offset 2. Relevant equations x = Vo cos(30)*t y = Yo + Vo*sin(30)t - 1/2gt^2 3. The attempt at a solution x = 5m - .288m = 4.772m 4.772m = Vo*cos(30)*t Vo = 4.772/cos(30) y = 2m + (4.772m/cos(30))*sin(30)t - 1/2(9.81)t^2 t = .987s Vo = 4.772/cos(30)*(.987s) = 5.44m/s Using same method b = 5.13m/s Found a picture for the problem on the net for better clarity: http://books.google.com/books?id=A_...esnum=3&ved=0CBEQ6AEwAg#v=onepage&q=&f=false"