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LightMech

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First time poster, site looks very informative so I thought I would make a post. This is for Mechanics class and now covering Dynamics. This is my take home problem.

A basket ball player shoots when she is 5 m from the backboard. Knowing that the ball has an intial velocity Vo at an angle of 30⁰ with the horizontal, determine the value of Vo when d is equal to (a) 228 mm, (b) 420 mm.

given info:

x: player is 5M from back board

y: initial height of ball 2m from floor, hoop is 3.048m from floor

angle: 30⁰

d: this is the distance from the back board or offset

x = Vo cos(30)*t

y = Yo + Vo*sin(30)t - 1/2gt^2

x = 5m - .288m = 4.772m

4.772m = Vo*cos(30)*t

Vo = 4.772/cos(30)

y = 2m + (4.772m/cos(30))*sin(30)t - 1/2(9.81)t^2

t = .987s

Vo = 4.772/cos(30)*(.987s)

= 5.44m/s

Using same method

b = 5.13m/s

Found a picture for the problem on the net for better clarity:

http://books.google.com/books?id=A_...esnum=3&ved=0CBEQ6AEwAg#v=onepage&q=&f=false"

A basket ball player shoots when she is 5 m from the backboard. Knowing that the ball has an intial velocity Vo at an angle of 30⁰ with the horizontal, determine the value of Vo when d is equal to (a) 228 mm, (b) 420 mm.

## Homework Statement

given info:

x: player is 5M from back board

y: initial height of ball 2m from floor, hoop is 3.048m from floor

angle: 30⁰

d: this is the distance from the back board or offset

## Homework Equations

x = Vo cos(30)*t

y = Yo + Vo*sin(30)t - 1/2gt^2

## The Attempt at a Solution

x = 5m - .288m = 4.772m

4.772m = Vo*cos(30)*t

Vo = 4.772/cos(30)

y = 2m + (4.772m/cos(30))*sin(30)t - 1/2(9.81)t^2

t = .987s

Vo = 4.772/cos(30)*(.987s)

= 5.44m/s

Using same method

b = 5.13m/s

Found a picture for the problem on the net for better clarity:

http://books.google.com/books?id=A_...esnum=3&ved=0CBEQ6AEwAg#v=onepage&q=&f=false"

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