Negating the statement: \exists M \in R such that \forall x\in S, x\leqM

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SUMMARY

The discussion centers on the negation of the mathematical statement \(\exists M \in R\) such that \(\forall x\in S, x \leq M\). The correct negation is established as \(\forall M \in R, \exists x \in S\) such that \(x \geq M\). A clarification is made that while \(x > M\) is a stronger condition, the original negation is accurate as stated. Participants confirm the correctness of the negation and express gratitude for the assistance provided.

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  • Understanding of quantifiers in mathematical logic
  • Familiarity with real numbers and sets
  • Basic knowledge of symbolic logic notation
  • Experience with mathematical proofs and negations
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  • Explore examples of negating statements involving sets
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Students of mathematics, particularly those studying logic, set theory, and real analysis, as well as educators seeking to clarify concepts related to quantifiers and negation.

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Homework Statement



[tex]\exists[/tex] M [tex]\in[/tex] R such that [tex]\forall[/tex] x[tex]\in[/tex] S, x[tex]\leq[/tex]M
Write in symbolic for the negation of the statement.

The Attempt at a Solution


[tex]\forall[/tex] M[tex]\in[/tex] R, [tex]\exists[/tex] x[tex]\in[/tex] S such that x[tex]\geq[/tex]M

Is this correct?
 
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It should be x > M, but otherwise yes.
 
Great. Thanks for the help.
 

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