Negative Fractional Exponent problem

  • Thread starter jdoyle
  • Start date
  • #1
7
0
Hi All,

Can anyone walk me through this problem. This is from an old med school entry test.

The answer is 81 but I can't work out how the x terms cancel.



3x(3x^ -1/3)^3

Thanks in advance

John
 

Answers and Replies

  • #2
281
2
[tex]\frac{3x}{(^3\sqrt{x})^3}3^3=\frac{3x}{x}3^3=27*3=81[/tex]

Given of course that x is not 0.
 
  • #3
7
0
Hi Meldraft,

It looks so simple I don't know why I didn't do it that way. Thanks very much.

John
 
  • #4
281
2
It's very easy to put that 3^3 in the denominator by accident :wink:
 

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