Simplify equation with negative exponents

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Homework Help Overview

The problem involves simplifying the expression (x-2 - y-2) / (x-1 + y-1), with a focus on understanding the implications of negative exponents and the equivalence of different forms of the answer.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss various methods for simplification, including factoring and removing negative exponents. Some express curiosity about the terminology for polynomials with negative exponents and their classification as rational functions.

Discussion Status

Several participants have shared their approaches and insights, noting that different methods yield equivalent results. There is recognition of the validity of multiple perspectives on simplification, though no consensus has been reached on a single preferred method.

Contextual Notes

Participants question the classification of expressions with negative exponents and explore the implications of simplifying fractions with differing forms. There is an acknowledgment of the complexity in determining which form is "better" based on context.

Boba-Feet
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Homework Statement


Simplify (x-2 - y-2) / (x-1 + y-1)


Homework Equations





The Attempt at a Solution


So I just factorised the numerator into x-1 - y-1 and x-1 + y-1. And was left with x-1 - y-1 as an answer. The textbook gives (y - x) / (xy) as the answer (no working shown). So after some substitution I've realized my answer and the textbook's are the same. But I would like to know how they got theirs and is it a simpler form of my answer?

And I read on the internet that polynomials with negative exponents are not called polynomials, is that true and what should they be called? Thanks a lot in advance :)
 
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To simplifying this equation is like simplifying any other fraction with a plus or minus in between it.

evaluate this:
\frac{1}{10} - \frac{1}{5} = ?

Then, imagine that x = 10 and y = 5
 
Starting with your result, you can write ##x^{-1}=\frac{1}{x}## and do the same with y, and combine the sum to a single fraction afterwards.

And I read on the internet that polynomials with negative exponents are not called polynomials, is that true and what should they be called? Thanks a lot in advance :)
Well, they are polynomials in a different variable (##x^{-1}## instead of x)...
As functions, they are called rational functions.
 
MY first thought was to get rid of those negative exponents by multiplying both numerator and denominator by x^2y^2. That gives
\frac{y^2- x^2}{xy^2- x^2y}= \frac{(y- x)(y+x)}{xy(x- y)}= \frac{y+ x}{xy}
 
OK I am able to see how the textbook arrived at it's answer.
I looked at it and initially thought to factorise because I saw the difference of two squares (x^-2 - y^-2).
But the textbook writer thought to remove the negative exponents first. Strange that both answers look so different but mean the same thing.

Thanks for the quick and helpful responses.
 
Last edited:
Boba-Feet said:
OK I am able to see how the textbook arrived at it's answer.
I looked at it and initially thought to factorise because I saw the difference of two squares (x^-2 - y^-2).
But the textbook writer thought to remove the negative exponents first. Strange that both answers look so different but mean the same thing.

Thanks for the quick and helpful responses.

It is really not strange at all; do you prefer to write (1/3) + (1/5) or 8/15? Which way is "better" depends on what you want to do with the answer.
 

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