Negative Free Energy - Physical Chemistry

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SUMMARY

The discussion centers on the preparation of hydrogen peroxide through two reactions, analyzing their Gibbs free energy changes (ΔG°rxn). Reaction 1, involving hydrogen and oxygen, has a ΔG°rxn of -120.4 kJ, indicating it is spontaneous and requires less energy under standard conditions. In contrast, Reaction 2, which uses water and oxygen, has a ΔG°rxn of +116.7 kJ, signifying it is nonspontaneous and requires additional energy. Therefore, Reaction 1 is the preferred method for producing hydrogen peroxide due to its negative free energy value.

PREREQUISITES
  • Understanding of Gibbs free energy and its implications in chemical reactions
  • Familiarity with standard conditions in thermodynamics
  • Knowledge of spontaneous vs. nonspontaneous reactions
  • Basic concepts of chemical reaction mechanisms
NEXT STEPS
  • Research the concept of Gibbs free energy in detail
  • Study the principles of thermodynamics related to reaction spontaneity
  • Explore various methods for synthesizing hydrogen peroxide
  • Learn about the impact of reaction conditions on ΔG°rxn values
USEFUL FOR

Chemistry students, physical chemists, and anyone involved in chemical synthesis or thermodynamic analysis will benefit from this discussion.

cvc121
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Homework Statement


Hydrogen peroxide can be prepared in several ways. One method is the reaction between hydrogen and oxygen, another method is the reaction between water and oxygen. Given the ΔG°rxn values for each reaction, which method (reaction 1 or 2) requires less energy under standard conditions?
1. H2(gas) + O2(gas) <---> H2O2(liquid) ΔG°rxn = -120.4 kJ
2. H2O(liquid) + 1/2 O2(gas) <---> H2O2(liquid) ΔG°rxn = +116.7 kJ

Homework Equations


N/A

The Attempt at a Solution


Would the answer be reaction 2 because it is lower in magnitude? I know that a negative free energy value corresponds to a spontaneous reaction and a positive value a nonspontaneous reaction but is the sign significant in this case?
 
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cvc121 said:
Would the answer be reaction 2 because it is lower in magnitude?
No
cvc121 said:
is the sign significant in this case?
Yes
 

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