I read with interest the thread here https://www.physicsforums.com/threads/bells-theorem-and-negative-probabilities.59163/ and was trying to find out more about how a negative probability might be interpreted. I came across this and wondered if anyone could shed more light on it. "Let us consider the situation when an attentive person A with the high knowledge of English writes some text T. We may ask what the probability is for the word “texxt” or “wrod” to appear in his text T. Conventional probability theory gives 0 as the answer. However, we all know that there are usually misprints. So, due to such a misprint this word may appear but then it would be corrected. In terms of extended probability, a negative value (say, -0.1) of the probability for the word “texxt” to appear in his text T means that this word may appear due to a misprint but then it’ll be corrected and will not be present in the text T." —Mark Burgin, Burgin, Mark (2010). "Interpretations of Negative Probabilities". http://arxiv.org/abs/1008.1287 [Mentor's note - edited to fix a link that was broken, probably by the forum software] Is the "misprint' here referring to the uncertainty principle in some way? Thanks.