Negative sign when finding forces from derivative of potential?

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Homework Help Overview

The discussion revolves around the concept of deriving forces from potential energy functions, specifically focusing on the signs associated with these derivatives in the context of Coulomb, gravitational, and harmonic potentials.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand whether the force should be expressed as f = +dV/dx or f = -dV/dx and is questioning the significance of the sign conventions used in these formulas.

Discussion Status

Some participants have provided guidance on the convention that the force is derived as f = -dV/dx, indicating that this formulation leads to forces pointing towards lower potential. The discussion appears to be exploring the implications of this sign convention without reaching a definitive consensus.

Contextual Notes

The original poster expresses uncertainty about the definitions of positive and negative directions in the context of forces and potentials, indicating a need for clarification on these conventions.

21joanna12
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Hi! I'm currently reading a book where they give the Coulomb potential, gravitational potential and harmonic potential as

+Q1Q2/4∏εx

-Gm1m2/x

+(1/2)qx2

I think I get the signs as they are used here, but when I am trying to find the force by taking the derivative of these with respect to x, I don't know whether to to f= +dV/dx or f= -dV/dx for any of them and I can't figure out the significance of the sign- which way is defined as +ve/-ve and why?

Sorry if I posted this is the wrong place or if it is not very clear :/ This is my first post of PF...

Thank you for any replies! :)
 
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F = -dV/dx

This way the force points "down" the slope to a lower potential.
 
Thank you! :)
 

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