Galilean transformation problem (Speed)

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Homework Help Overview

The problem involves a girl riding a bicycle at constant speed and the timing of events as perceived from different reference frames. The specific context is the application of Galilean transformations to analyze the speed of the bicycle based on the distance between two events observed from the cyclist's frame and the bus stop frame.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of speed using the Galilean transformation equation and question the significance of a negative result in the context of speed being a scalar quantity. There is also exploration of the reference frames used for the events and how they affect the interpretation of displacement.

Discussion Status

The discussion is ongoing, with participants examining the implications of the negative speed calculation and clarifying the reference frames involved. Some participants are questioning the assumptions made about the direction of motion and the resulting displacements.

Contextual Notes

There is a focus on the definitions of displacement in different frames of reference, and participants are considering how the choice of origin affects the interpretation of the events. The problem is framed within the constraints of a homework assignment, which may limit the depth of exploration.

Ace.
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Homework Statement



A girl is riding a bicycle along a straight road at constant speed, and passes a friend standing at a bus stop (event #1). At a time of 60 s later the friend catches a bus (event #2)
If the distance separating the events is 126 m in the frame of the girl on the bicycle, what is the bicycle's speed?

Homework Equations


u = u' + v




The Attempt at a Solution


u = u' + v
can be written as:
Δx/t = Δx'/t + v
v = Δx/t - Δx'/t
v = 0m/60s - 126m /60s
v = -126 m/ 60s
v = -2.1 m/s

Just wondering if the negative holds any significance? I know we're talking about speed which is scalar but how come the calculation gives a negative?
 
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Ace. said:

Homework Statement



A girl is riding a bicycle along a straight road at constant speed, and passes a friend standing at a bus stop (event #1). At a time of 60 s later the friend catches a bus (event #2)
If the distance separating the events is 126 m in the frame of the girl on the bicycle, what is the bicycle's speed?

Homework Equations


u = u' + v




The Attempt at a Solution


u = u' + v
can be written as:
Δx/t = Δx'/t + v
v = Δx/t - Δx'/t
v = 0m/60s - 126m /60s
v = -126 m/ 60s
v = -2.1 m/s

Just wondering if the negative holds any significance? I know we're talking about speed which is scalar but how come the calculation gives a negative?
It should be +2.1 m/s. This is because the Δx' represents the displacement of the second event minus the displacement of the first. So v = 0/60 - (-126/60).

You are using the cyclist's reference frame with the origin at the cyclist to determine u' and the bus stop person's (bsp) reference frame with the bsp at the origin to determine u. There are two events: 1. the origins coincide and 2. the bsp enters the bus.

In the cyclist's frame these events occur at 0 and -126 m. using the direction of v as the +x direction. So Δx' = -126m. In the bsp's frame, they both occur at the origin.

AM
 
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Andrew Mason said:
In the cyclist's frame these events occur at 0 and -126 m.

Why wouldn't it be +126 m if she is moving forward?
 
Ace. said:
Why wouldn't it be +126 m if she is moving forward?
To the cyclist, the ground is moving backwards.
 

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