Nested Open Sets: Example & Intersection

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Homework Help Overview

The discussion revolves around finding an example of an infinite collection of nested open sets in the context of real analysis, specifically focusing on their intersection being closed and non-empty.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants explore the idea of starting with an open interval, such as (0,1), and creating smaller nested intervals. There is discussion about using intervals of the form (-1/n, 1/n) and the concept of taking the middle one-third of a set. Questions arise regarding the rigor of these approaches and the implications of the intersection of these sets.

Discussion Status

The discussion is active with various approaches being suggested. Some participants are questioning the clarity and rigor of the proposed methods, while others are providing alternative suggestions for constructing the nested open sets. There is a general sense of collaboration as participants seek to refine their ideas.

Contextual Notes

Participants are navigating the constraints of the problem, including the requirement for the intersection of the sets to be closed and non-empty, and are considering the implications of their chosen intervals.

cragar
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Homework Statement


Give an example of an infinite collection of nested open sets.
o_1 \supseteq o_2 \supseteq o_3 \supseteq o_4 ...
Whose intersection \bigcap_{n=1}^{ \infty} O_n is
closed and non empty.

Homework Equations


A set O \subseteq \mathbb{R} is open if for all points, a \in O
there exists an \epsilon neighborhood V_{\epsilon}(a) \subseteq O

The Attempt at a Solution


It seems like if we started with the open interval (0,1) and then took a smaller interval that was nested inside the original interval, and then just kept doing this until we enclosed one point in the interval.
 
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cragar said:
It seems like if we started with the open interval (0,1) and then took a smaller interval that was nested inside the original interval, and then just kept doing this until we enclosed one point in the interval.

Yes, that's the idea.

Can you make this rigorous??
 
Can I just take the middle one-third of the set.
so after n operations i will have \frac{1}{3^n}
 
I cannot really tell where you are going with that last response. It might be a little easier if you consider intervals of the form (-\frac{1}{n},\frac{1}{n}).
 
cragar said:
Can I just take the middle one-third of the set.
so after n operations i will have \frac{1}{3^n}

What do you mean?? 1/3^n is just a number.

Just find sets that get smaller and smaller each time.

start with ]-1,1[, then ]-1/2,1/2[. Then what??
 
ok so like jgens said use ( \frac{-1}{n} , \frac{1}{n})
And then eventually after n goes to infinity I will have 0 as my enclosed point.
so if I make an \epsilon radius around 0 i will contain points inside of O the original set. Would the set zero it self be closed be cause if we make
an \epsilon radius around 0 it won't contain elements that are in the set zero itself.
 
Or, if you really want 1/3^n, you could use O_n= (-1/3^n, 1/3^n).
 
ok, thanks everyone for the help
 

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