Net force acting on a ping-pong ball

[bbbbb]

Homework Statement

A ping-pong ball has a weight of 0.50 N. While in contact with a paddle the paddle exerts a force of 7.8 N at 29° above the horizontal.

Relevant Equations

Determine the net force acting on the ball at this instant.

w= 0.50N, Fn= 7.8N, angle= 29
Fnet= Fn*fd* costheta
= 7.8*0.50*cos(29
= 3.41
is my answer correct

 

[PeroK]

Homework Statement:: A ping-pong ball has a weight of 0.50 N. While in contact with a paddle the paddle exerts a force of 7.8 N at 29° above the horizontal.
Relevant Equations:: Determine the net force acting on the ball at this instant.

w= 0.50N, Fn= 7.8N, angle= 29
Fnet= Fn*fd* costheta
= 7.8*0.50*cos(29
= 3.41
is my answer correct

What's the logic behind your calculation?

 

[vela]

Fnet= Fn*fd* costheta
= 7.8*0.50*cos(29
= 3.41
is my answer correct

3.41 cows? No, that's not even a force. How could it be correct?

 

[bbbbb]

what do I like the steps to get the answer to the question

 

[haruspex]

Homework Statement:: A ping-pong ball has a weight of 0.50 N. While in contact with a paddle the paddle exerts a force of 7.8 N at 29° above the horizontal.
Relevant Equations:: Determine the net force acting on the ball at this instant.

w= 0.50N, Fn= 7.8N, angle= 29
Fnet= Fn*fd* costheta
= 7.8*0.50*cos(29
= 3.41
is my answer correct

I cannot think of any situation where it would make sense to multiply two forces.
Have you drawn a free body diagram? That should always be the first step.
Do you know how to add forces vectorially?

 

[bbbbb]

I do not know how to add forces vectorially?
Yes but I am not sure if it's correct.

 

[haruspex]

I do not know how to add forces vectorially?
Yes but I am not sure if it's correct.

Is that yes you have drawn a FBD? If so, please try to post it.
You do not have any chance of solving this question if you do not know how to add forces. Have you not been taught? Any notes?
Plenty of resources on the net, just search for "how to add forces" or "how to add vectors".

 

[bbbbb]

We have two forces acting on the ball.
the force of gravity, there is no component is the x direction and all of the force is in the negative x direction
i will do the components of both using fcosθ for the x- component and fsinθ for the y-component

 

[PeroK]

We have two forces acting on the ball.
the force of gravity, there is no component is the x direction and all of the force is in the negative x direction
i will do the components of both using fcosθ for the x- component and fsinθ for the y-component

Here's an approximate answer. We have a force of $7.8N$ and a force of $0.5N$, which is small compared to the first. The answer should be close to $7.8N$ in a direction not much different from the direction of the larger force. The answer can't be $3.41N$ or anything like that.

 

[bbbbb]

For the Fnet I got 7.57N and the angle has 25.7

 

[PeroK]

For the Fnet I got 7.57N and the angle has 25.7

That looks a lot better!

 

[bbbbb]

Thank you.