Net force on particle 1 due to particle 2 in vector form?

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SUMMARY

The net force on particle 0 due to particle 1 is calculated using Coulomb's Law, expressed as \(\vec{F_{12}}=\frac{kq_1q_2}{r_{12}^2}\vec{e_{12}}\). In this scenario, particle 0 is fixed at the origin with charge \(q_0\), while particle 1 is positioned at (0, d1, 0) with charge \(q_1\). The force on particle 0 from particle 1 is directed along the positive y-axis, represented as \(\frac{kq_0q_1}{d_1^2}j\).

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Corey Bacon
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Homework Statement


Hi all,
I have this quiz on MasteringPhysics, but I can't seem to get the right answer.[/B]
Consider two positively charged particles, one of charge q0 (particle 0) fixed at the origin, and another of charge q1 (particle 1) fixed on the y-axis at (0,d1,0). What is the net force F⃗ on particle 0 due to particle 1?
Express your answer (a vector) using any or all of k, q0, q1, d1, i^, j^, and k^.

If someone wouldn't mind giving me some advice, I would much appreciate it.
Thanks

Homework Equations


Columns Law

The Attempt at a Solution


$$\frac{kq_0q_1}{d_1^2}j$$
 
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The direction of the force is important too.
 
Force on q0 by q1 acts in which direction ?
 
You have write down the part of the answer.
The complete Coulomb law is:
$$\vec{F_{12}}=\frac{kq_1q_2}{r_{12}^2}\vec{e_{12}}$$
for ##\vec{F_{12}}## is the force ##q_1## makes on ##q_2## and ##e_{12}## is the unit vector from ##q_1## toward ##q_2.##
It may help you find out the correct direction of the force.
 
41643ec5136542b93edf3f6b56fb90f0.png
and putting r(cap) = r(vector)/r
upload_2015-8-4_16-27-0.png
 

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