Net Resistance of Parallel Circuits: Solve It Now!

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SUMMARY

The net resistance of resistors connected in parallel can be calculated using the formula 1/Rp = 1/R1 + 1/R2 + 1/R3. In this discussion, the resistors of 100 ohms, 250 ohms, and 400 ohms yield a total resistance of approximately 61 ohms when calculated correctly. The arithmetic involves finding a common denominator, which in this case is 6000 ohms, leading to the equation 1/Rp = 60 + 24 + 15/6000 ohms. The final result confirms that Rp equals 61 ohms.

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  • Understanding of Ohm's Law
  • Basic knowledge of parallel circuits
  • Ability to perform arithmetic with fractions
  • Familiarity with resistor values and units of measurement
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  • Learn how to calculate total resistance in series circuits
  • Study the concept of equivalent resistance in complex circuits
  • Explore the impact of resistor values on circuit performance
  • Practice solving parallel circuit problems with varying resistor values
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kllindsey
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Question: Determine the net resistance of 100 ohms, 250 ohms and 400 ohms connected in a parallel.

I have no clue how to figure this out. I have read and reread the section in my book and it is not helping. Please help.
 
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Well what have you tried so far?
 
1/Rp = 1/100 + 1/250 + 1/400

I know the answer is:

1/Rp = 60 + 24 + 15/6000 ohms
Rp = 6000 ohms/99 = 61 ohms

I just have no clue where these numbers are coming from!
 
Well I haven't a clue how you got from your formula to your second line.

I agree that your answer of 61 is close enough though.

Can you not do the arithemetic involved in your first line?
 
Your answer and the books answer are the same. They just multiply the fractions so there is a common denominator (However odd that denominator is)
 

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