Or: if y= arccos(x) then x= cos(y). Differentiate that to find dx/dy= -sin(y) so that
dy/dx= -1/sin(y)= -1/sin(arccos(y)).
Use trig identities to simplify that (change sin(arccos(y)) to cos(arccos(y))=y) or think about a right triangle with "near side" of length y and hypotenuse of length 1. What is the length of the "opposite side"? Whatr is the sine?