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## Homework Statement

A charged particle is observed to have a total energy of 0.642 MeV when it is moving at 0.700c. If this particle enters a linear accelerator and its speed is increased to 0.980c, what is the new value of the particle's total energy?

## Homework Equations

Rest mass energy:

E

_{0}=mc

^{2}

Kinetic energy:

K=([tex]\gamma[/tex]-1)mc

^{2}

Total energy:

E=E

_{0}+K

## The Attempt at a Solution

I tried to solve for the rest mass energy using the original speed and total energy, but got stuck. I also tried to set up a ratio of old total E on top of new total E, but that didn't give me the correct answer.

Can anyone help? Thanks!