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New value of the particle's total energy?

  • Thread starter vrobins1
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Homework Statement



A charged particle is observed to have a total energy of 0.642 MeV when it is moving at 0.700c. If this particle enters a linear accelerator and its speed is increased to 0.980c, what is the new value of the particle's total energy?

Homework Equations


Rest mass energy:
E0=mc2

Kinetic energy:
K=([tex]\gamma[/tex]-1)mc2

Total energy:
E=E0+K


The Attempt at a Solution


I tried to solve for the rest mass energy using the original speed and total energy, but got stuck. I also tried to set up a ratio of old total E on top of new total E, but that didn't give me the correct answer.

Can anyone help? Thanks!
 

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