- #1
shadowboy13
- 20
- 0
So for starters the area of an entire circle has 360º,right?
So we can say that: ##1∏r^2## is ##\equiv## to ##360º##
So by that logic ##0.5∏r^2## is ##\equiv## to ##180º##
And finally ##0.25∏r^2## is ##\equiv## to ##90º##
Divide both sides by 9, and you get : ##0.25∏r^2/9## is ##\equiv## to ##10º##
From that it's much simpler to multiply both sides by some variable.
Simple right?
So we can say that: ##1∏r^2## is ##\equiv## to ##360º##
So by that logic ##0.5∏r^2## is ##\equiv## to ##180º##
And finally ##0.25∏r^2## is ##\equiv## to ##90º##
Divide both sides by 9, and you get : ##0.25∏r^2/9## is ##\equiv## to ##10º##
From that it's much simpler to multiply both sides by some variable.
Simple right?