I Newbie learning Heat Exchanger

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The discussion centers on the calculation of the logarithmic mean temperature difference (LMTD) for heat exchangers, specifically addressing a formula that yields an incorrect result of 24.7°C. Participants emphasize the importance of understanding LMTD and the correct notation for logarithms, clarifying that the natural logarithm (ln) should not be confused with base 10 logarithms. There is a call for a complete problem statement to provide context for the calculation. Additionally, there is a critique of the original post for lacking clarity and detail. Understanding the fundamentals of LMTD is essential for accurate heat exchanger analysis.
Clemens Khoo
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Hi guys, I got a question here for this Heat Exchanger.
Please refer the description.
May I know why the answer is 24.7? How?
"ln" stand for?
How to calculate?
ΔTLMTDcf = 20 - 30
ln20/30 ←(What is "In"?)
= 24.7°C ←(Why the answer is 24.7? How?)
 
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Hello @Clemens Khoo,
:welcome: ##\qquad ##!​

In the first place: the answer is NOT 24.7 but 24.7 °C
(I don't even know the question -- you really should post the full problem statement ! -- , but I bet my career on that).

Then: you want to look up LMTD to find out what the exercise is about. If you don't know, then either you've been sleeping or not attended at all.

Ln is natural logarithm, which google. The notation ##\operatorname{ln}## is for dimwits, excel users and engineers who would otherwise interpret the corrrect notation ##\log## as a logarithm base 10.
(*)

And ##\log(20/30) ## is not 24.7 !

[edit]Ah, I see: you meant to write $${20-30\over\log(20/30)}$$ and didn't notice PF posts ignore spaces​

for this Heat Exchanger.
Please refer the description.
What HX ? What description ?

----------------

(*) Just kidding. See here.

##\ ##
 
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