Newton's law of universal gravitation

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Homework Help Overview

The discussion revolves around Newton's law of universal gravitation, specifically focusing on determining the SI units of the gravitational constant G from the equation F = GMm/r², where F represents the gravitational force, M and m are the masses, and r is the distance between the objects.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore dimensional analysis to derive the units of G, with various attempts to manipulate the equation and clarify the units of force, mass, and distance.

Discussion Status

Several participants have provided insights into the dimensional analysis process, while others express confusion about the units of mass and the simplification steps. There is an ongoing exploration of the correct units and how to derive them from the equation.

Contextual Notes

Some participants question the definitions and assumptions regarding the units of mass, particularly in relation to the context of the problem. There is also mention of the need for clarity on whether constants should be simplified in the final answer.

chocolatelover
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Hi everyone,

Could someone please help me on this problem?

Homework Statement



Newton's law of universal gravitation is represented by the following equation where F is the magnitude of the gravitational force exerted by one small object on another, M and m are the masses of the objects, and r is a distance.
F = GMm/r2
Force has the SI units kg·m/s2. What are the SI units of the proportionality constant G?

Homework Equations





The Attempt at a Solution



Would it be m/kg s^2?

Thank you very much
 
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Well, use dimensional analysis: in classical mechanics, primary units are Mass, Time, and Space.
You know the dimensions of F, M,m,and r, so, that means you have only 1 var with 1 equation: linear determinate.

Well, in your attempt you say m/kg?!, SI units of m are Kg, so, m/kg is meaningless(and it's not correct), try google something about dimensional analysis, to see how it works. dimensional analysis is SUPER helpful in a lot of situations..:P

Littlepig
 
unit on LHS must equal the unit on the RHS for the equation to make sense. So altogether GMm/r^2 must has unit of Force: Kg. m/s^2... and you can now work out unit G must be
 
Thank you very much

I still don't really understand it. I tried doing cross multiplication and I got G=(kgm)(r^2)/Mms^2 or Kgr^2/Ms^2. Is that anywhere close?
 
G=\frac{Fr^2}{Mm}

Unit of Force(F) is ___? (and now in SI units)
Unit of distance(r) is ___?
Unit of Mass(M,m) is ___?

When you get those 3 replace them into the equation and simplify.
 
Thank you very much

Unit of Force(F) is ___? (and now in SI units)
Unit of distance(r) is ___?
Unit of Mass(M,m) is ___?

When you get those 3 replace them into the equation and simplify.

This is what I did:

I new that the distance had to be in m, so r^2=m^2. I also knew that the mass was kg/m^3 and the force was kgm/s^2. Do I then just need to simplify this?

G=(kgm/s^2)(m^2)/(kg/m^3)(kg/m^3)

Does that look right?

thank you very much
 
chocolatelover said:
This is what I did:

I new that the distance had to be in m, so r^2=m^2. I also knew that the mass was kg/m^3 and the force was kgm/s^2. Do I then just need to simplify this?

Why did you put mass as kg/m^3? Isn't mass just kg?

The force is correct and r is correct. but what you put as mass is off
 
Thank you very much

Since I have M and m, would it be (kg)(kg)?

So, G=(kg/m^3)(m^2)/(kg)(kg)
G=1/mkg

Does that look right?

Thank you very much
 
chocolatelover said:
Thank you very much

Since I have M and m, would it be (kg)(kg)?

So, G=(kg/m^3)(m^2)/(kg)(kg)
G=1/mkg

Does that look right?

Thank you very much

Yes M and m would be (kg)(kg)


G=(kgms^-2)(m^2)/(kg)(kg)

now simplify that
 
  • #10
Is it m^3/kgs^2? I don't understand how you got s^-2 or 1/s^2? Could you please explain that to me?

Thank you very much
 
  • #11
chocolatelover said:
Is it m^3/kgs^2? I don't understand how you got s^-2 or 1/s^2? Could you please explain that to me?

Thank you very much

This is a constant. Always start with the unit you want in your answer. Then make all the other units cancel by either adding factors in the numerator or denominator. Normal practice is to never simplify constants, but you should check with your instructor to see if he actually wants that.
 
  • #12
Thank you very much

Regards
 

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